Just stick with simple rockets 2 I think, New people might want to download this but can't find the game because it was renamed and the name is good enough anyways in my opinion.
I'm 2.5 years late but I wanted to let any others struggling with orbit inclinations that you're supposed to be using a formula to deduct the correct launch angle to achieve it, here, I'll explain. The launch inclination formula goes as follows, Cos(i)=Sin(A)Cos(O) where i will be the orbit inclination that you want, A will be the launch inclination (The angle that you launch at), And O will be the inclination of the launch pad.
Now to the younger players don't get freaked out, I'll explain
Say you want an orbit inclination of 30 degrees and you're launching at DCS pad which has an inclination of 0 degrees since it's situated on the equator, you'll plug these into the formula which will result in this: Cos(30)=Sin(A)Cos(0), you may recognize that this formula is basically just algebra, simply think of Sin(A) as x and solve, we bring sin(A) to the left of the formula and divide Cos(30) by Cos(0) which will look like this: Sin(A)=(Cos(30)/Cos0), (USE A CALCULATOR TO SOLVE THIS!!!), one this is solved you'll get the value of A which will most likely be a long string of random decimals, simply plug them into inverse sin (sin-1), this will look like
sin-1(0.8860254038) which will result in an angle of 60 degrees meaning that in order to get an orbit inclination of 30 degrees whilst launching from DCS pad you'll need to make sure that your inclination of 60 degrees (on the orange circle in the nav ball).
I know that I'm a few years late but I wanted to let any others struggling with orbit inclinations that you're supposed to be using a formula to deduct the correct launch angle to achieve it, here, I'll explain. The launch inclination formula goes as follows, Cos(i)=Sin(A)Cos(O) where i will be the orbit inclination that you want, A will be the launch inclination (The angle that you launch at), And O will be the inclination of the launch pad.
Now to the younger players don't get freaked out, I'll explain
Say you want an orbit inclination of 30 degrees and you're launching at DCS pad which has an inclination of 0 degrees since it's situated on the equator, you'll plug these into the formula which will result in this: Cos(30)=Sin(A)Cos(0), you may recognize that this formula is basically just algebra, simply think of Sin(A) as x and solve, we bring sin(A) to the left of the formula and divide Cos(30) by Cos(0) which will look like this: Sin(A)=(Cos(30)/Cos0), (USE A CALCULATOR TO SOLVE THIS!!!), one this is solved you'll get the value of A which will most likely be a long string of random decimals, simply plug them into inverse sin (sin-1), this will look like
sin-1(0.8860254038) which will result in an angle of 60 degrees meaning that in order to get an orbit inclination of 30 degrees whilst launching from DCS pad you'll need to make sure that your inclination of 60 degrees (on the orange circle in the nav ball).
I'm 2.5 years late but I wanted to let any others struggling with orbit inclinations that you're supposed to be using a formula to deduct the correct launch angle to achieve it, here, I'll explain. The launch inclination formula goes as follows, Cos(i)=Sin(A)Cos(O) where i will be the orbit inclination that you want, A will be the launch inclination (The angle that you launch at), And O will be the inclination of the launch pad.
Now to the younger players don't get freaked out, I'll explain
Say you want an orbit inclination of 30 degrees and you're launching at DCS pad which has an inclination of 0 degrees since it's situated on the equator, you'll plug these into the formula which will result in this: Cos(30)=Sin(A)Cos(0), you may recognize that this formula is basically just algebra, simply think of Sin(A) as x and solve, we bring sin(A) to the left of the formula and divide Cos(30) by Cos(0) which will look like this: Sin(A)=(Cos(30)/Cos0), (USE A CALCULATOR TO SOLVE THIS!!!), one this is solved you'll get the value of A which will most likely be a long string of random decimals, simply plug them into inverse sin (sin-1), this will look like
sin-1(0.8860254038) which will result in an angle of 60 degrees meaning that in order to get an orbit inclination of 30 degrees whilst launching from DCS pad you'll need to make sure that your inclination of 60 degrees (on the orange circle in the nav ball).
@LeMagicBaguette Yes, I understand but do you do the same things for the bodies of irregularly shaped cars? How would you make this? https://www.simpleplanes.com/a/eCB0gu/AGT-supercar
Just stick with simple rockets 2 I think, New people might want to download this but can't find the game because it was renamed and the name is good enough anyways in my opinion.
+4 3.1 years ago5 and a half years later and this bug is still present unfortunately
13 days agoI'm 2.5 years late but I wanted to let any others struggling with orbit inclinations that you're supposed to be using a formula to deduct the correct launch angle to achieve it, here, I'll explain. The launch inclination formula goes as follows, Cos(i)=Sin(A)Cos(O) where i will be the orbit inclination that you want, A will be the launch inclination (The angle that you launch at), And O will be the inclination of the launch pad.
20 days agoNow to the younger players don't get freaked out, I'll explain
Say you want an orbit inclination of 30 degrees and you're launching at DCS pad which has an inclination of 0 degrees since it's situated on the equator, you'll plug these into the formula which will result in this: Cos(30)=Sin(A)Cos(0), you may recognize that this formula is basically just algebra, simply think of Sin(A) as x and solve, we bring sin(A) to the left of the formula and divide Cos(30) by Cos(0) which will look like this: Sin(A)=(Cos(30)/Cos0), (USE A CALCULATOR TO SOLVE THIS!!!), one this is solved you'll get the value of A which will most likely be a long string of random decimals, simply plug them into inverse sin (sin-1), this will look like
sin-1(0.8860254038) which will result in an angle of 60 degrees meaning that in order to get an orbit inclination of 30 degrees whilst launching from DCS pad you'll need to make sure that your inclination of 60 degrees (on the orange circle in the nav ball).
I know that I'm a few years late but I wanted to let any others struggling with orbit inclinations that you're supposed to be using a formula to deduct the correct launch angle to achieve it, here, I'll explain. The launch inclination formula goes as follows, Cos(i)=Sin(A)Cos(O) where i will be the orbit inclination that you want, A will be the launch inclination (The angle that you launch at), And O will be the inclination of the launch pad.
20 days agoNow to the younger players don't get freaked out, I'll explain
Say you want an orbit inclination of 30 degrees and you're launching at DCS pad which has an inclination of 0 degrees since it's situated on the equator, you'll plug these into the formula which will result in this: Cos(30)=Sin(A)Cos(0), you may recognize that this formula is basically just algebra, simply think of Sin(A) as x and solve, we bring sin(A) to the left of the formula and divide Cos(30) by Cos(0) which will look like this: Sin(A)=(Cos(30)/Cos0), (USE A CALCULATOR TO SOLVE THIS!!!), one this is solved you'll get the value of A which will most likely be a long string of random decimals, simply plug them into inverse sin (sin-1), this will look like
sin-1(0.8860254038) which will result in an angle of 60 degrees meaning that in order to get an orbit inclination of 30 degrees whilst launching from DCS pad you'll need to make sure that your inclination of 60 degrees (on the orange circle in the nav ball).
I'm 2.5 years late but I wanted to let any others struggling with orbit inclinations that you're supposed to be using a formula to deduct the correct launch angle to achieve it, here, I'll explain. The launch inclination formula goes as follows, Cos(i)=Sin(A)Cos(O) where i will be the orbit inclination that you want, A will be the launch inclination (The angle that you launch at), And O will be the inclination of the launch pad.
20 days agoNow to the younger players don't get freaked out, I'll explain
Say you want an orbit inclination of 30 degrees and you're launching at DCS pad which has an inclination of 0 degrees since it's situated on the equator, you'll plug these into the formula which will result in this: Cos(30)=Sin(A)Cos(0), you may recognize that this formula is basically just algebra, simply think of Sin(A) as x and solve, we bring sin(A) to the left of the formula and divide Cos(30) by Cos(0) which will look like this: Sin(A)=(Cos(30)/Cos0), (USE A CALCULATOR TO SOLVE THIS!!!), one this is solved you'll get the value of A which will most likely be a long string of random decimals, simply plug them into inverse sin (sin-1), this will look like
sin-1(0.8860254038) which will result in an angle of 60 degrees meaning that in order to get an orbit inclination of 30 degrees whilst launching from DCS pad you'll need to make sure that your inclination of 60 degrees (on the orange circle in the nav ball).
@TheVizzyLucky Thanks!
1.4 years ago@LeMagicBaguette Yes, I understand but do you do the same things for the bodies of irregularly shaped cars? How would you make this? https://www.simpleplanes.com/a/eCB0gu/AGT-supercar
1.8 years ago@Insanity Thanks man, that's just the answer I was looking for
1.8 years agoHow do I assign crew members to my craft?
2.2 years agoyes, but it should be close
2.8 years ago@GrandmasterPotato just read the delta-v map in reverse lol
2.8 years agoXLM is better.
3.1 years ago