``````      Droo
``````

1 Droo Day - around 14 hrs
Rotational Velocity at equator-158 m/s
Mass= 2.383561897×10^23kg.
Area-2.04x 10^13 m2
Escape Velocity-4997.4 m/s
Revolution period=58 days apprx

``````   Luna
``````

Mass: 3.00E+21 kg
Orbital Velocity at 30 km: 722.1 m/s
Orbital Height above Droo (Avg.): 37,200,500 m
Revolution period-4d6hrs apprx
Rotation period-4d 6 hr apprx(tidal locking)

``````   Cylero
``````

Mass: 2.554717E+22 kg
Orbital Velocity at 150 km: 1435 m/s
Orbital Height above the Sun: 22,655 Mm
Escape Velocity: 2242.68 m/s

Feel free to tell more !
Let's bring a science revolution to SR2!

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• 1,660 tsampoy

If only science was added to sr2

7 months ago
• 6 Maal

@MAHADI Cylero does have same orbital speed as Kerbin in KSP dho

7 months ago

let's go to Mars!

7 months ago
• @Aerospacer thanks for finding error,I'll fix it

8 months ago
• @PriyanshuRoy I am look to wiki.
Must be sqrt(2GM/r)

8 months ago
• 148 GR00G0

8 months ago
• 101 Rexy

@jacksawild Your delta V may be slightly more accurate. I solved deltaV by using the rocket equation but alas I utilized the vacuum exhaust velocity for both atmospheric and orbital flight which will contribute some error. My method was manual reading of rocket masses at each stage using 8 different rockets all entering into a 115x115 then summing a total dV.

I'll try to put together a much more thorough experimental run at some point over the next few days.

The average atmospheric density between surface and 100km is about 5.21 PSI

8 months ago
• @Aerospacer I used formula sqrt (GM/r)

8 months ago
• @Rexy "I've been doing various test runs and delta V required to achieve LDO appears to be approximately 5.57 km/s"

Which way are you launching? Going east I can get 100km * 100km orbit with about 4.3km/s. Even less with an efficient design.

According to my totally scientific sample size of 1, the edge of Droo SOI is 95775.5km

8 months ago
• P.S. Recalculate of escape velosity.
Zero-level orbital speed = 3533.7 m/s.

8 months ago
• +1 interesting fact about Droo -
His average density ~27.5 t/m^3.
Sadly, the same mistake as in KSP - it's unrealistic...
(Osmium density ~22.6 t/m^3)

+1 8 months ago
• 101 Rexy

I've been doing various test runs and delta V required to achieve LDO appears to be approximately 5.57 km/s

Atmosphere air pressure can also be roughly approximated by the function:
p(h)=14.7exp(-(x/40000)^2)
units being PSI,

that was calculated experimentally taking engine thrust measurements every kilometer to look at dropoff, best fitting a gaussian packet, determining engine chamber pressure in vacuum, then solving for external air pressure as a function of altitude.

+1 8 months ago
• Also did some SCIENCE with Cylero and came up with this:
Mass: 2.554717E+22 kg
Orbital Velocity at 150 km: 1435 m/s
Orbital Height above the Sun: 22,655 Mm
Escape Velocity: 2242.68 m/s

+1 8 months ago
• I got some info on Luna. Not sure how accurate it is, so I will probably update it soon, but here are some rough estimates:

Mass: 3.00E+21 kg
Orbital Velocity at 30 km: 722.1 m/s
Orbital Height above Droo (Avg.): 37,200,500 m

+1 8 months ago

+1 8 months ago
• @DrCoconut1245
Earth mass is: 5.972 × 10^24 kg

So earth is about 5 times wider and 25 times more massive.

+1 8 months ago
• @jackawild Can we get comparisons to earth? The only thing I recognize is that the surface gravity is almost earths.

8 months ago
• @PriyanshuRoy

M=ar^2/G

a = surface gravity = 9.798 m/s^2
r^2 = radius squared: 1274200^2 = 1623585640000 meters
G = gravity constant = 6.6726 x 10-11N-m^2/kg^2

So a bit more precise: 2.38406199992806×10^23kg, which alters droostationary height to 8803730 meters.

+3 8 months ago
• @jacksawild Thanks! But I didn't need to place a geostationary satellite.I just want to bring together the information.
PS how did you find mass of droo?

8 months ago
• 27 eonn44

@PriyanshuRoy thanks

8 months ago
• Good info. So to calculate geostationary altitude:

G = 6.67381x10^-11
M = 2.383561897×10^23 (mass of Droo)
t = 2540160000 (14 hours * 60 * 60)

cuberoot((6.67381x10^-11 * 2.383561897×10^23 * 2540160000) / 4* pi^2) = 10,077,834

Subtract radius of Droo (1274200 ) = 8803634.6 metres

About as close as I could get without RCS: https://youtu.be/GY3HpcblSpM

It has a period of 14hours and it seems to be sitting over the same continent. So I'd say it's pretty damn close.

+4 8 months ago
• 172 TR2002

Cool!

8 months ago